Review of Basic Algebra
(A Review for SSI and Challenge 2000)
I. Exponents
If n is a positive integer, then an represents the product of n factors each of which is a.
In general,
Example: a x a x a= a3 and 2 x 2 x 2 x 2 = 24 = 16
Definition: Given the expression
, where a, n, and b are real numbers (a, n, and b
R ), a is the base and n is the exponent or power.
Example: In 52 , 5 is the base and 2 is the exponent.
Note: If n is a positive integer and if a and b are real numbers such that an = b, then a is said to be an nth root of b and may be written
( or
).
For Negative Integral Exponents:
If n is a positive integer, 
.
Example: 3-2 =
Positive Fractional Exponents:


, where m and n are positive integers.
Example:

Negative Fractional Exponent:
Example: 
Zero Exponent:
a 0 = 1, a
0
Example: b 0 = 1 , 5 0 = 1, and 333 0 = 1
General Laws of Exponents:
a p a q =
= a p + q
Example: 52 x 53 = (5) (5) x (5) (5) (5) = 5 5 = 3125
( a p )q =
= a pq
Example: ( 3 2 )3 = ( 32 ) ( 32 ) ( 32 ) = 3 (2) (3) = 3 6 = 729
= a p
= a p
a-q = a p-q , a
0
Recall: a-q =
Example:
( ab ) p =
= a p b p
Example: (2 x 3)2 = (2)(3) x (2)(3) = 22 x 32 = 4 x 9 = 36
( a / b) p ,
=
, b
0
Example:
Some Important Formulas (only a very few are to be memorized!)
A) (a+ b) (a - b) = (a )( a) - (a)( b) + (a)( b) - (b)( b) = a2 - ab + ab - b2 = a2 - b2
Example: (3a + b)(3a - b) = (3a)( 3a)-(3a)( b) + (3a)(b) - (b)(b) = 9a2 -3ab+ ab - b2 = 9a2 - b2
(a + b) ( a - b) = a2 - b2
B) (a + b)(a + b) = (a + b)2 = (a)( a) + (a )( b) + (a )( b) + (b )( b) = a2 + ab + ab + b2 = a2 + 2ab + b2
Example: (2a + b)(2a + b) = (2a + b)2 = (2a)( 2a) + (2a)( b) + (2a)( b) + (b)( b) = 4a2 + 2ab + 2ab + b2 = 4a2 + 4ab + b2
(a + b) ( a + b) = a2 + 2ab + b2
C) (a -b)(a - b) = (a -b)2 = (a)( a) - (a)(b ) - (a)( b) + (b)(b) = a2 - ab -ab + b2 = a2 -2ab + b2
Example: (2a -b) ( 2a -b) = ( 2a - b)2 = (2a)( 2a) - (2a )(b) - (2a)(b) + (b)(b) = 4a2 - 2ab - 2ab + b2 = 4a2 - 4ab + b2
(a - b)(a - b) = a2 - 2ab + b2
D) (x + a )( x + b ) = (x )( x) + ( b)( x) + ( a )( x) +( a )( b) = x2 + bx + ax + ab = x2 + (a + b ) x + ab
Example: (3x + 2a) (3x + 2b) = (3x)(3x) + ( 2b)( 3x) + (2a)(3x) + (2a)( 2b)= 9x2 + 6bx + 6ax + 4ab
(TO MEMORIZE OR KNOW!): (x + a)(x + b) = x2 + (a + b)x + ab
III. Quadratic Formula
Consider the polynomial: ax2 + bx + c.
ax2 + bx + c = 0 , where a
0.
The solutions of this quadratic equation are the values of x for which the above polynomial is zero. They are also called roots or zeroes of the plynomial ax2 + bx + c. These root can be expressed in terms of the coefficients a, b, and c as shown below.
Given
, the discriminant
or
x =
.
A) If the discriminant is equal to zero (b2 - 4ac = 0) the roots are real and equal.
Example: Given 4x2 - 12x + 9 = 0 a = 4 , b = -12 and c = 9
Therefore, x =
Since the discrinimant is 0, the roots are equal.
Note: A rational number is one that can be expressed in the fractional form
, where and b are integers and
. It can further be defined as the ratio of two integers.
Example: 5 = 5/1 , 1/2 , 3/4 and 4/5 are rational numbers.
and
are irrational because they cannot be written as the ratio of two integers.
B) If the discriminant is less than zero (b2 - 4ac < 0), the roots are complex numbers.
Example: Given x2 + 3x + 5 = 0 a = 1 , b = 3 and c = 5
Therefore, x =
x1 =
and x2 =
. Note well that
The above roots are complex numbers, i.e., any number written as
Both are real numbers.
Example:
is a pure imaginary number.
A complex number may be defined as a real number plus an imaginary number and may be written in the form z = a + ib.
C) If the discriminant is greater than zero ( b2 - 4ac > 0 ) then the roots are real and unequal.
Example: Given 5x2 + 2x - 9 = 0 a = 5 , b = 2 and c = - 9
Therefore, x =
x1 =
and x2 =
Since the discriminant is greater than zero, the roots and unequal.